a wire is bent to form four semicircles all with diameters of 32 cm, how long is the wire? round to the nearest hundredth
200.96
To find the length of the wire, we need to calculate the circumference of each semicircle and then add them together.
The formula to calculate the circumference of a circle is given by:
C = π * d
where C is the circumference and d is the diameter.
Given that the diameter of each semicircle is 32 cm, we can calculate the circumference of a single semicircle as follows:
C1 = 1/2 * π * 32
C1 ≈ 50.27 cm (rounded to the nearest hundredth)
Since there are four semicircles, we can multiply the circumference of a single semicircle by four to get the total length of the wire:
Total length = 4 * C1
Total length ≈ 4 * 50.27 ≈ 201.08 cm (rounded to the nearest hundredth)
Therefore, the length of the wire is approximately 201.08 cm when rounded to the nearest hundredth.
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Item 8
A wire is bent to form four semicircles. How long is the wire to the nearest hundredth?
length: about
cm
Well, what if the diameter is 53 cm?
The length of the wire will be equal to the circumference of four semicircles that were made from it.
So, if the diameter of one semicircle is 32 cm, then the radius is = 32/2 cm = 16 cm.
Now, the circumference of a circle is 2*(pi)*(radius).
Here we have a semi-circle, so its circumference is half of of a circle = (pi)*(radius).
Then, circumference of 4 semi-circles is = 4*(pi)*(radius).
The value of pi is 22/7.
So, length of wire is = 4*(22/7)*16 cm = 200 cm (after rounding to the nearest hundreth).