A body of mass 10kg is acted upon by a constant force 20N for 3secs. Calculate the K.E gained by the body.
i do not know it pls give me the solution
Kll
To calculate the kinetic energy gained by the body, we need to use the equation:
Kinetic Energy (K.E) = 1/2 * mass * velocity^2
First, let's find the velocity of the body using Newton's second law of motion:
Force = mass * acceleration
Rearranging the equation, we have:
acceleration = Force / mass
Given that the force acting on the body is 20N and the mass of the body is 10kg, we can substitute these values into the equation:
acceleration = 20N / 10kg = 2 m/s^2
Now, let's find the final velocity of the body using the equation of motion:
velocity = initial velocity + acceleration * time
Since the body starts from rest (initial velocity = 0), we can simplify the equation to:
velocity = acceleration * time
Substituting the values we have:
velocity = 2 m/s^2 * 3 s = 6 m/s
Now that we have the velocity of the body, we can calculate the kinetic energy:
K.E = 1/2 * mass * velocity^2
Substituting the given mass of 10kg and the velocity of 6 m/s:
K.E = 1/2 * 10kg * (6 m/s)^2
= 1/2 * 10kg * 36 m^2/s^2
= 180 Joules (J)
Therefore, the kinetic energy gained by the body is 180 Joules (J).