Solve the system below:
Y= x^2-4
Y= -4
A. 0, -4
B. -4, 0
C. 0, -4)(-4,0
D. No solution
-4 = x^2 - 4
x = 0
then y = -4
A
To solve the system of equations, we need to find the values of x and y that make both equations true.
Given:
1) Y = x^2 - 4
2) Y = -4
Since both equations equal Y, we can set them equal to each other:
x^2 - 4 = -4
To solve this equation, we can first add 4 to both sides:
x^2 = 0
Next, we take the square root of both sides to solve for x:
√(x^2) = √0
|x| = 0
The absolute value of x is equal to 0, which means x can only be 0.
So, x = 0.
Now we can substitute x = 0 into either of the original equations to find the value of y.
Let's use equation 1:
Y = x^2 - 4
Y = 0^2 - 4
Y = -4
Therefore, the solution to the system of equations is (x, y) = (0, -4).
The correct answer is A. 0, -4.