The length of a rectangle is2cm more than its breadth ,and its perimeter is28 cm find the length and breadth of rectangle
From the prompt, we know that:
a) L = W + 2
b) Perimeter = 28 = 2L + 2W
Where I call breadth W
The easiest way to solve this system is by substitution. Plug in (a)'s value of L into b, yielding
28 = 2(W+2) + 2W.
From here, isolate and solve for W. You should get W = 6cm. We now revisit equation (a), plugging in our solved value of W, yielding
L = 2 + (6),
so L = 8 cm.
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To find the length and breadth of the rectangle, we can set up a system of equations based on the given information.
Let's assume that the breadth of the rectangle is 'x' cm. According to the given information, the length of the rectangle is 2 cm more than the breadth, so its length is 'x + 2' cm.
The perimeter of a rectangle can be calculated by adding the lengths of all four sides. In this case, the perimeter is 28 cm. So, we can set up the equation:
2(length + breadth) = perimeter
Substituting the values, we have:
2(x + (x + 2)) = 28
Simplifying, we get:
2(2x + 2) = 28
4x + 4 = 28
4x = 24
Dividing both sides of the equation by 4, we get:
x = 6
Therefore, the breadth of the rectangle is 6 cm.
To find the length of the rectangle, we can substitute the value of x in the equation for length:
Length = x + 2 = 6 + 2 = 8 cm
So, the length of the rectangle is 8 cm.
Therefore, the length and breadth of the rectangle are 8 cm and 6 cm, respectively.