Math
posted by Lola .
The equation y=4.9t^2+3.5t+5 describes the height (in meters) of a ball thrown upward at 3.5 meters per second from 5 meters above the ground. In how many seconds will the ball hit the ground? Express your answer as a common fraction.
Thank you for your help!

the ball hits the ground when y=0.
If you want a fraction, then let's get rid of the decimals:
y = 1/10 (49t^2 + 35t + 50)
= 1/10 (7t+5)(107t)
y=0 when t = 10/7
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