Ln2+Lnx=1
Solve for x
Ln2+Lnx=1
ln(2x) = 1
by definition of ln
e^1 = 2x
x = e/2
To solve the equation ln(2) + ln(x) = 1, we can use properties of logarithms.
First, we can combine the logarithms on the left side of the equation by using the property of logarithmic addition: ln(a) + ln(b) = ln(a * b).
Therefore, we have: ln(2 * x) = 1.
Next, we can convert the equation into exponential form. Since ln(x) is the natural logarithm of x, e raised to the power of ln(x) will give us x.
In this case, we have: e^(ln(2 * x)) = e^1.
Simplifying further, we have: 2 * x = e.
Finally, we solve for x by dividing both sides of the equation by 2:
x = e / 2.
So, the solution to the equation ln(2) + ln(x) = 1 is x = e / 2.