A force of 80N acts on a body initially at rest and moves 72m in 6s. If the force is removed after 6s calculate how far the body moves after 6s
x = xo + Vo t + (1/2) a t^2
72 = (1/2) a (36)
a = 4 m/s^2
v = Vo + a t
at t = 6
v = 0 + 4*6
v = 24 m/s
that is initial Vo at 6
if there is no friction, it continues at 24 m/s for 6 s
24 * 6 = 144 m more
thanks a lot Damon
Well, if the force is removed after 6 seconds, the body will probably take a nap. It's hard work moving around! So, after 6 seconds, I'm pretty sure the body will stay right where it is and enjoy a little break. No more moving for that guy!
To calculate how far the body moves after 6 seconds when the force is removed, we can use the formula for distance traveled:
distance = initial velocity * time + (1/2) * acceleration * time^2
However, since the body is initially at rest, the initial velocity is 0. Additionally, when the force is removed, there is no acceleration acting on the body anymore. Therefore, the formula simplifies to:
distance = initial velocity * time
Since the initial velocity is 0, we can conclude that the body does not move any further after 6 seconds when the force is removed.
To determine how far the body moves after 6 seconds, we need to use the equation of motion that relates force, mass, acceleration, and displacement:
F = m * a,
where F represents the force, m is the mass, and a is the acceleration. In this case, the force (F) is given as 80 Newtons. However, we don't have the mass or acceleration provided, so we'll need to use another equation.
We can use the equation that relates acceleration, initial velocity, and displacement:
s = ut + (1/2) * a * t^2,
where s represents the displacement, u is the initial velocity, t is the time, and a is the acceleration.
Since the body is initially at rest, the initial velocity (u) is zero, and the equation simplifies to:
s = (1/2) * a * t^2.
Given that the body moves a distance of 72 meters in 6 seconds, we can substitute these values into the equation and solve for acceleration:
72 = (1/2) * a * (6^2).
72 = (1/2) * a * 36.
72 = 18a.
a = 72/18.
a = 4 m/s^2.
Now that we have the acceleration, we can use it to find the displacement after the force is removed. From the equation F = m * a, we know that if the force is removed, then the acceleration becomes zero.
Therefore, using the equation s = ut + (1/2) * a * t^2 again, with a = 0, we have:
s = 0 * t + (1/2) * 0 * t^2,
s = 0.
So, after the force is removed, the body does not move any further (i.e., it remains at rest). The displacement after 6 seconds is 0 meters.