# Algebra

posted by Callie

For two consecutive positive even integers, the product of the smaller and twice the larger is 160. Find the integers.

1. Steve

the integers are 2k and 2k+2

(2k)*2(2k+2) = 160
k(k+1) = 20

20=4*5, so k=4

The numbers are 8 and 10

## Similar Questions

1. ### Math

The greater of two consecutive even integers is six less than twice the smaller. Find the integers. Let the smaller be x. That means that the larger is x+2. From your statement x+2=2x-6 Solve for x. I hope this helps. Thanks for asking.
2. ### Math

The greater of two consecutive even integers is six less than twice the smaller. Find the integers. The greater of two consecutive even integers is six less than twice the smaller. Find the integers How about x + 2 = 2x - 6 almost …
3. ### Algebra

The larger of two positive integers is five more than twice the smaller integer. The product of the integers is 52. Find the integers. Must have an algebraic solution.
4. ### Integers

The larger of two positive integers is five more than twice the smaller integer. The product of the integers is 52. Find the integers.
5. ### algebra

Find two consecutive even integers such that the sum of the larger and twice the smaller is 62. PLEASE HELP I DON'T GET IT!/:
6. ### algebra

The larger of two consecutive integers is 10 more than 4 times the smaller. Find the integers.
7. ### Math

If the larger of two consecutive integers is subracted from twice the smaller integer, then the result is 21. Find the integers.
8. ### Algebra 1

The larger of two consecutive integers is 7 greater than twice the smaller. Find the integers. A) 4,5 B) -8,-9 C) -5,-6
9. ### math

The product of two consecutive positive even integers is 48. Find the integers.
10. ### Math

The smaller of two consecutive even integers is 2 more than twice the larger. Find the numbers.

More Similar Questions