probobility

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4 -letter "words" are formed using the letters A, B, C, D, E, F, G. How many such words are possible for each of the following conditions?
(a) No condition is imposed.
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(b) No letter can be repeated in a word.
Your answer is :
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(c) Each word must begin with the letter A.
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(d) The letter C must be at the end.
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(e) The second letter must be a vowel.
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  • probobility -

    a) no condition: 7x7x7x7 = 7^4 = 2401

    b) no repeats: 7x6x5x4 = 840

    c) begin with A, can I repeat the others ?
    I will assume I can:
    1x7x7x7 = 343

    d) same as c)
    7x7x7x1 = 343

    e) 2nd letter is a vowel
    7x2x7x7 = 686

    In c), d) and e) I assumed that letters can be repeated, you did not say otherwise.
    If they cannot be repeated , it is easy to change the calculations

  • probobility -

    Thank you! I was able to do A & B but c,d,& e I would figure out. thanks again

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