At what height above Earth's surface is the gravitational acceleration reduced from its sea-level value by 0.20%?
At what height above Earth's surface is the gravitational acceleration reduced from its sea-level value by 2.0%?
At what height above Earth's surface is the gravitational acceleration reduced from its sea-level value by 20%?
What am I doing wrong...
for .2%
g=9.8-(.002*9.8)
.0196 =9.7804
r=sqrt(GM/g)
sqrt(3.9886*10^14)/9.7804
6386044.4
6386044.4-6370000=16044 m or aprx 16 km
am i not using the right equation?