# chem12

posted by George

for the equilibrium
2HI(g)--- H2(g) + I2 k eq = 8.0
2.0 mol of HI are placed in a 4.0 L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases.
Inital
2HI 0.5mol/l
H2 =0
I2=0
change
2HI= -2x
H2=+x
I2=+x
equilibrium
2HI = 0.5-2x
H2= x
I2=x
keq= H2 x I2/ HI^2
8.0= (x) (x)/0.5-2x
taking sqr root of both sides
2.828=x/0.5-2x
0.2154=x
so 0.2154 mol/L of H2 and I2 at equilibrium and
2HI = 2x=2(0.2154)= 0.4308
0.5-0.4308=0.069
2HI=0.069 mol/L
If you could look this over to see if I have done this right. I appreciate any help you can give.

## Similar Questions

1. ### Chemistry

The following system is at equilibrium,at 699K in a 5L container. H2(g)+I2(g)--->2HI(g) Kc = 54.9 Initially,the system had 2.50 moles of HI.What is the moles of H2 at equilibrium?
2. ### Chemistry

Need help in AP chemistry on Equilibrium When heated, hydrogen sulfide gas decomposes according to the equation 2 H2S(g) ⇄ 2 H2(g) + S2(g) A 3.40 g sample of H2S(g) is introduced into an evacuated rigid 1.25 L container. The …
3. ### Chemistry

Consider the following equilibrium: 2HI(g) *are in equilibrium with* H2(g) = I2(g) Keq = 81.0 A 2.00L container is initially filled with 4.00 mol HI. Calculate the [HI] at equilibrium. *I don't know how to put the equilibrium sign …
4. ### Chemistry***

A mixture containing 19.8 moles of H2 and 7.2 mole of I2 was allowed to reach equilibrium in a 5 L closed vessel at ToC according to the equation: H2 (g) + I2 (g) 2HI (g) At equilibrium, 14 moles of H2 was present. The equilibrium …
5. ### chem

For the reaction: A+B <-----> 2C (all gases) 2.0 mol A, 2.8 mol B and 1.0 mol C are placed in a 2.0 L container and allowed to reach equilibrium. When equilibrium is established [C]=0.75 M. Calculate all equilibrium concentrations. …
6. ### chem12

1.0 mol of each of the gases, CO, H20, CO2 and H2 are placed in a 2.00L container and allowed to reach equilibrium. It is found at equilibrium 0.40 mol of CO is present. Calculate the value of K eq for the system. C0(g) + H20(g)--- …
7. ### chem 12

for the equilibrium 2HI(g)--- H2(g) + I2 k eq = 8.0 2.0 mol of HI are placed in a 4.0 L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases. Inital 2HI 0.5mol/l H2 =0 …
8. ### chem 12

1.0 mol of each of the gases, CO, H20, CO2 and H2 are placed in a 2.00L container and allowed to reach equilibrium. It is found at equilibrium 0.40 mol of CO is present. Calculate the value of K eq for the system. C0(g) + H20(g)--- …
9. ### chem12

2HI(g)--H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases Initial 2HI=0.5 mol/L H2= 0 I2=0 change 2HI= -2x …
10. ### chem12

2HI(g)--H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases Initial 2HI=0.5 mol/L H2= 0 I2=0 change 2HI= -2x …

More Similar Questions