posted by George .
for the equilibrium
2HI(g)--- H2(g) + I2 k eq = 8.0
2.0 mol of HI are placed in a 4.0 L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases.
2HI = 0.5-2x
keq= H2 x I2/ HI^2
8.0= (x) (x)/0.5-2x
taking sqr root of both sides
so 0.2154 mol/L of H2 and I2 at equilibrium and
2HI = 2x=2(0.2154)= 0.4308
If you could look this over to see if I have done this right. I appreciate any help you can give.