Evaluate sum please help

posted by Crystal

Evaluate the sum
∑3 =0 (-1)k × 2k-1/2k-1

  1. Steve

    surely (2k-1)/(2k-1) = 1

    So, the sum is

    ∑ (-1)^k = (-1)^3 + (-1)^4 + (-1)^5 + (-1)^6 = -1+1-1+1 = 0

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