Calculate the force required to pull a copper ball of radius 2.00 cm upward through a fluid at the constant speed 6.00 cm/s. Take the drag force to be proportional to the speed, with proportionality constant 0.950 kg/s. Ignore the buoyant force.
N
Don't know the density of copper, but if you find it you can get the mass from 4/3 pi r^3 times density.
Now you have an mg force down and the drag force (.06 m/s)(.950 kg/s).
Sum those two and that the force you need to balance.
To calculate the force required to pull the copper ball upward through a fluid at a constant speed, we need to consider the drag force acting on the ball.
The drag force is given by the equation:
Fd = k * v
Where:
- Fd is the drag force
- k is the proportionality constant (0.950 kg/s in this case)
- v is the speed of the ball relative to the fluid (6.00 cm/s)
Now, let's calculate the drag force:
Fd = 0.950 kg/s * 6.00 cm/s
First, we need to convert the speed to meters per second:
6.00 cm/s = 0.06 m/s
Now, we can substitute the values into the equation:
Fd = 0.950 kg/s * 0.06 m/s
Fd = 0.057 N
Therefore, the force required to pull the copper ball upward through the fluid at a constant speed of 6.00 cm/s is 0.057 N.