Precalc
posted by Anonymous
Using logarithms to rewrite the expression:
1.) log4.(4)^3x=
2.) 6 log6 36=
3.) 3 log 2 1/2=
4.) 1/4 log4 16

Steve
by definition, log_b(b^z) = z
So,
log_4(4^3x) = 3x
6 log_6(36) = 6 log_6(6^2) = 6*2 = 12
3 log_2(1/2) = 3 log_2(2^1)) = 3*1 = 3
1/4 log_4(16) = 1/4 log_4(4^2) = 1/4 * 2 = 1/2
Respond to this Question
Similar Questions

Calculus
How do I rewrite log4 1=0 as an equivalent exponential equation? 
Precalculus
I'm studying for my precalc exam and have completed 42 practice problems. I have 3 I need to answer that I can't. Please help. What is the base of the function G(x) = log subscript b x if it's graph has points (16,4)? 
Algebra II
Solve, round to four decimal places if necessary: log4(x9)=2 Answer: x9=4^2 x9=16 x=11 log4(z)+log4(z3)=1 Answer: z+z3=1 2z=4 z=2 Thanks for checking my work. 
Logarithms
Solve log4 x + log4(x2)=log4(15) I know how do the example in my book but I don't know what I'm doing wrong here. log4 x + log4(x2)=log4(15) log4 [x + log4(x2)]=log4(15) (x^2 + x)=4 x^2 + x4=0 
Algebra 2
Simplify: 1. 2log10^5+log10^4 2. 2log3^6log3^4 3. log4^40log4^5 4. log4^3log4^48 I need to see all of the steps. Thanks 
Math
Evaluate the expression without using a calculator: log4(2)= ____? 
Math(Please check)
solve for x: log4 X  log4 2 = 2 log(2x) = 2 Now what do I do? 
Math
solve for x: log4 X  log4 2 = 2 log(2x) = 2 Now what do I do? 
Logarithm help
Write each expression as a single logarithm I need help really fast. I have to finish this by today. log4^3 + 1/2log4^8  log4^2 
precalc
I don't understand how to do these w/o calc. I tried to write it in a way that will make someone understand how to read it. Hope I typed it clear enough.Thanks so much for the help anyone! How to find the exact value of logarithm: …