Precalc

posted by Anonymous

Using logarithms to rewrite the expression:

1.) log4.(4)^3x=
2.) 6 log6 36=
3.) 3 log 2 1/2=
4.) 1/4 log4 16

1. Steve

by definition, log_b(b^z) = z

So,

log_4(4^3x) = 3x
6 log_6(36) = 6 log_6(6^2) = 6*2 = 12
3 log_2(1/2) = 3 log_2(2^-1)) = 3*-1 = -3
1/4 log_4(16) = 1/4 log_4(4^2) = 1/4 * 2 = 1/2

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