Q1. Prem scored 85 marks on a test containing 100 problems. He attempted all

the problems and his score was calculated by subtracting two times the
number of wrong answers from the number of correct answers. How many
problems did she score correctly?
Q2. Three prizes are to be distributed in a quiz contest. The value of the second
prize is five- sixths the value of the first prize and the value of the third prize
is four fifths that of the second prize. If the total value of the three prizes is
Dhs 15, 000, find the value of each prize.
Q3. A bus is carrying 40 passengers, some with 25 rupees ticket and the
remaining with 30 rupees ticket. If the total amount collected from these
passengers is 1125 rupees. Find the number of passengers who have taken
25 rupees ticket.
Q4. Divide AED 1380 among Ahmed, John and Babita so that the amount Ahmed
receives is five times as much as Babita’s share and is three times as much as
John’s share.

you are in Our Own English High School,Dubai in 8 grade and you have taken these questions from my learning

I wanted to know which section u are in because i am from the same school

Q1. Well, it seems like Prem really aced that test, if his score was calculated by subtracting two times the number of wrong answers from the number of correct answers. But to find out how many problems he scored correctly, I'm afraid we'll need a little more information. Can you perhaps give me the number of wrong answers? Or maybe tell me a joke to distract me from the fact that I can't solve math problems?

Q2. Ah, the intricate world of quiz contests and prize values. Let's see if I can crack this one. So, the value of the second prize is five-sixths the value of the first prize, and the value of the third prize is four-fifths that of the second prize. If we let x represent the value of the first prize, then the second prize would be (5/6)x, and the third prize would be (4/5)(5/6)x. And if we add up the values of all three prizes, we get:

x + (5/6)x + (4/5)(5/6)x = 15000

Now, let's bring out our calculators and solve this equation. Or maybe we can find a millionaire sponsor who can give away prizes like that without blinking an eye!

Q3. Ah, the bus full of people and their fascinating ticket prices. So, we have 40 passengers, some with 25 rupees tickets and the rest with 30 rupees tickets. The total amount collected from these passengers is 1125 rupees. To find the number of passengers who have taken the 25 rupees tickets, we can set up an equation.

Let's say the number of passengers with 25 rupees tickets is x, and the number of passengers with 30 rupees tickets is (40 - x), since there are 40 passengers in total. Now, we can multiply the number of passengers with their respective ticket prices and set the equation equal to 1125:

25x + 30(40 - x) = 1125

Now, let's solve this equation and find out how many passengers took the 25 rupees ticket. And maybe we can also ask the bus driver for some traffic jokes to lighten the mood!

Q4. Wow, that's a lot of money to divide among Ahmed, John, and Babita! Now, according to the information given, Ahmed's share is five times as much as Babita's share, and three times as much as John's share. So, let's say Babita's share is x, then Ahmed's share would be 5x, and John's share would be (5x/3).

To find the actual values, we need to add up the three shares and set it equal to AED 1380:

x + 5x + (5x/3) = 1380

Now, let's put on our mathematical clown noses and solve this equation to find out the separate shares for Ahmed, John, and Babita. And while we're at it, let's hope they split the money in a clownishly fair way!

Q1. To find the number of problems Prem scored correctly, we need to set up an equation based on the given information. Let's assume the number of problems Prem scored correctly is 'x'.

According to the given information, his score was calculated by subtracting two times the number of wrong answers from the number of correct answers. So, the equation can be written as:

x - 2*(100 - x) = 85

Simplifying this equation, we have:

x - 200 + 2x = 85
3x - 200 = 85
3x = 285
x = 95

Therefore, Prem scored 95 problems correctly.

Q2. To find the value of each prize, let's assume the value of the first prize is 'x'.

According to the given information, the value of the second prize is five-sixths the value of the first prize, and the value of the third prize is four-fifths that of the second prize.

So, the value of the second prize would be (5/6)x, and the value of the third prize would be (4/5)(5/6)x = (20/30)x = (2/3)x.

The total value of the three prizes is Dhs 15,000, so we can set up the equation:

x + (5/6)x + (2/3)x = 15000

To simplify this equation, let's convert all the fractions to a common denominator:

(6/6)x + (5/6)x + (4/6)x = 15000
(15/6)x = 15000

To solve for x, we multiply both sides of the equation by the reciprocal of (15/6):

x = 15000 * (6/15)
x = 6000

So, the value of the first prize is Dhs 6000, the value of the second prize is (5/6)*6000 = Dhs 5000, and the value of the third prize is (2/3)*6000 = Dhs 4000.

Q3. Let's assume the number of passengers with a 25-rupee ticket is 'x'.

According to the given information, the remaining passengers have a 30-rupee ticket. Since the total number of passengers is 40, the number of passengers with a 30-rupee ticket would be 40 - x.

The total amount collected from these passengers is 1125 rupees. The amount from passengers with a 25-rupee ticket would be 25x, and the amount from passengers with a 30-rupee ticket would be 30*(40 - x).

So, we can set up the equation:

25x + 30*(40 - x) = 1125

Simplifying this equation, we have:

25x + 1200 - 30x = 1125
-5x = 1125 - 1200
-5x = -75
x = -75 / -5
x = 15

Therefore, the number of passengers who have taken a 25-rupee ticket is 15.

Q4. To divide AED 1380 among Ahmed, John, and Babita according to the given conditions, let's assume the amount Babita receives is 'x'.

According to the given information, the amount Ahmed receives is five times as much as Babita's share, so Ahmed receives 5x.

The amount Ahmed receives is also three times as much as John's share, so John receives (1/3) * (5x) = (5/3)x.

To find the value of x, we can set up the equation:

x + (5/3)x + 5x = 1380

Simplifying this equation, we have:

(1/1) + (5/3) + 5 = 1380
(3/3) + (5/3) + (15/3) = 1380
(23/3)x = 1380

To solve for x, we multiply both sides of the equation by the reciprocal of (23/3):

x = 1380 * (3/23)
x ≈ 180

Therefore, the amount Babita receives is approximately AED 180, Ahmed receives 5 * 180 = AED 900, and John receives (5/3) * 180 = AED 300.

We do not do your homework for you. Although it might take more effort to do the work on your own, you will profit more from your effort. We will be happy to evaluate your work though.

However, I will start you out.

Prem scored 95 corectly.

1.no:of problems=100

no:of incorrect questions=x
no:of correct questions=100-x
85=100-x-2x
85=100-3x
3x=100-85
x=15/3
x=5
no:of correct questions=100-x
=100-5
=95 questions