The box plots below show the average daily temperatures in January and December for a U.S. city:
two box plots shown. The top one is labeled January. Minimum at 0, Q1 at 10, median at 12, Q3 at 13, maximum at 16. The bottom box plot is labeled December. Minimum at 1, Q1 at 5, median at 18, Q3 at 25, maximum at 35
What can you tell about the means for these two months?
A. The Mean for December is higher than January's mean
B. it is almost certain that January's mean is higher
C. There is no way of telling what the means are
D.The narrow iqr for January causes its mean to be lower
I think it is c
The box plots below show attendance at a local movie theater and high school basketball games:
two box plots shown. The top one is labeled Movies. Minimum at 60, Q1 at 65, median at 95, Q3 at 125, maximum at 150. The bottom box plot is labeled Basketball games. Minimum at 90, Q1 at 95, median at 125, Q3 at 145, maximum at 150.
Which of the following best describes how to measure the spread of the data?
A. The IQR is a better measure of spread for movies than it is for basketball games.
B. The standard deviation is a better measure of spread for movie than it is for basket games
C. The IQR is the best measurement of spread for games and movies
D. The Standard deviation is the best measurement of spread for games and movies
I think it is a
same this question is hard and math 1 is about to end and ill fail. ;(
I need help on these two too
For the first question, to determine the means for January and December, you would need additional information such as the actual temperature values or a data set for both months. Box plots only provide information about the distribution of the data, not the mean. Therefore, the correct answer is C. There is no way of telling what the means are based solely on the box plots.
For the second question, to measure the spread of the data, you can consider the interquartile range (IQR) and the standard deviation. The IQR is the range between the first quartile (Q1) and the third quartile (Q3) and provides information about the spread of the middle 50% of the data. The standard deviation measures the average deviation of each data point from the mean and provides a measure of overall variability.
Looking at the given box plots, the IQR can be calculated for both movies and basketball games. Therefore, the correct answer is A. The IQR is a better measure of spread for movies than it is for basketball games. This is because the IQR for movies (125 - 65 = 60) is larger than the IQR for basketball games (145 - 95 = 50), indicating a greater spread of data in the movies attendance. The standard deviation can also be calculated, but the IQR provides a more specific measure of spread for skewed or non-normal distributions, which is often the case in attendance data.