What is the distance between point P(-2, 1, 3) and point Q(-1, 4, -2) to the nearest tenth?
35.1 units
9.3 units
18.4 units
5.9 units
My answer: 18.4 units
nope ...
distance = √((-2+1)^2 + (1-4)^2 + (3+2)^2 )
= √( 1 + 9 + 25)
= √35
= appr 5.92
their choice is 5.9
To find the distance between two points in a three-dimensional space, you can use the distance formula. The distance formula is derived from the Pythagorean theorem.
The formula is as follows:
distance = √((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2)
In this case, the coordinates of point P are (-2, 1, 3), and the coordinates of point Q are (-1, 4, -2).
Substituting the values into the formula:
distance = √((-1 - (-2))^2 + (4 - 1)^2 + (-2 - 3)^2)
distance = √((1)^2 + (3)^2 + (-5)^2)
distance = √(1 + 9 + 25)
distance = √35
Rounded to the nearest tenth, the distance between point P and point Q is approximately 5.9 units.
Therefore, the correct answer is 5.9 units, not 18.4 units.