A solution is prepared by adding 1.50 mol glucose to 3.50 mol water. What is the vapor pressure of the solution at 25 oC given that the vapor pressure of pure water is 23.8 torr?

To calculate the vapor pressure of the solution, we can use Raoult's Law. According to Raoult's Law, the vapor pressure of a solution is equal to the mole fraction of the solvent multiplied by the vapor pressure of the pure solvent.

Step 1: Calculate the mole fraction of water (solvent) in the solution.
Mole fraction of water (X_water) = Number of moles of water / Total number of moles in the solution

Given:
Number of moles of water (n_water) = 3.50 mol
Number of moles of glucose (n_glucose) = 1.50 mol

Total number of moles in the solution = n_water + n_glucose
= 3.50 mol + 1.50 mol
= 5.00 mol

Mole fraction of water (X_water) = 3.50 mol / 5.00 mol
= 0.70

Step 2: Calculate the vapor pressure of the solution using Raoult's Law.
Vapor pressure of the solution (P_solution) = X_water * Vapor pressure of pure water (P_water)

Given:
Vapor pressure of pure water (P_water) = 23.8 torr

P_solution = 0.70 * 23.8 torr
= 16.66 torr

Therefore, the vapor pressure of the solution at 25°C is approximately 16.66 torr.

To find the vapor pressure of the solution, we first need to calculate the mole fraction of water in the solution. We can use the formula:

Mole fraction of water = moles of water / (moles of water + moles of glucose)

In this case, the moles of water is 3.50 mol, and the moles of glucose is 1.50 mol. Plugging these values into the formula:

Mole fraction of water = 3.50 mol / (3.50 mol + 1.50 mol) = 3.50 mol / 5.00 mol = 0.70

Next, we can use Raoult's law to calculate the vapor pressure of the solution. According to Raoult's law, the vapor pressure of a solution is equal to the mole fraction of the solvent (in this case, water) multiplied by the vapor pressure of the pure solvent.

Vapor pressure of the solution = Mole fraction of water * Vapor pressure of pure water

Plugging in the values:

Vapor pressure of the solution = 0.70 * 23.8 torr = 16.66 torr

Therefore, the vapor pressure of the solution at 25 °C is approximately 16.66 torr.

mols glucose = 1.50

mols water = 3.50
total mols = 1.50 + 3.50 = ?
X(mol fraction) H2O = mols water/total mols.
Psolution = Xsolvent*Po solvent