Functions & Trig
posted by Kerry .
evaluate each function at the given value:
f(n)=n^6+31n^4+26n^3+20n^2+33n20
when n=6
I was thinking that I should do synthetic division, but I've tried it a few times and I can't get it to work out correctly.
Please help!

A) put the value 6 into the equation everywhere you see an n
B) calculate
f(6) = 6^6 + 31(6)^4 + 26(6)^3 + 20(6)^2 + (33)(6)  20
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