Determine the number of grams present in 3.11x 10^23 atoms of water
Molar mass of H2O = 18.0 g/mol
18 g ------> 6.02x10^23 atoms
g -------> 3.11x10^23 atoms
( 3.11x10^23) * 18 / 6.02x10^23
5.598x10^24 / 6.02x10^23
= 9.299 gramas
hope thi helps!.
9.299 grams
To determine the number of grams present in 3.11x10^23 atoms of water, you need to follow these steps:
1. Begin by understanding the molecular formula of water, which is H2O. It consists of two hydrogen atoms and one oxygen atom.
2. Find the molar mass of water. The molar mass is calculated by adding up the atomic masses of all the atoms in the molecule. The atomic masses are usually given on the periodic table. For water, the atomic mass of hydrogen (H) is approximately 1 gram/mol, and the atomic mass of oxygen (O) is approximately 16 grams/mol. Adding these values gives a molar mass of water (H2O) of approximately 18 grams/mol.
3. Use Avogadro's number to convert the given number of atoms to moles. Avogadro's number, which is approximately 6.022 x 10^23, represents the number of particles (atoms, molecules, or ions) in one mole of a substance. By dividing the given number of atoms (3.11 x 10^23) by Avogadro's number, you can find the corresponding number of moles.
Moles = Number of atoms / Avogadro's number
= 3.11 x 10^23 atoms / 6.022 x 10^23
≈ 0.516 moles
4. Finally, multiply the number of moles by the molar mass of water to find the number of grams:
Grams = Moles x Molar mass
≈ 0.516 moles x 18 grams/mol
≈ 9.288 grams
Therefore, 3.11 x 10^23 atoms of water is approximately equal to 9.288 grams.