what mass of zinc will be required to react completely with 100cm3 of a 1.0M hcl.
To determine the mass of zinc required to react completely with 100 cm3 of a 1.0M HCl solution, we need to follow these steps:
Step 1: Write the balanced chemical equation for the reaction between zinc and hydrochloric acid:
Zn + 2HCl -> ZnCl2 + H2
Step 2: Calculate the number of moles of HCl present in 100 cm3 (or 0.1 L) of the 1.0M solution:
Molarity (M) = moles/volume (L)
1.0M = moles/0.1 L
moles of HCl = 1.0M * 0.1 L = 0.1 moles
Step 3: Use the stoichiometry from the balanced chemical equation to determine the moles of zinc required. From the equation, we can see that 1 mole of zinc reacts with 2 moles of HCl:
moles of Zn = 0.1 moles of HCl * 1 mole of Zn / 2 moles of HCl
moles of Zn = 0.05 moles
Step 4: Calculate the molar mass of zinc. This is found by adding the atomic masses of zinc's individual elements, which are 65.38 g/mol for zinc (Zn):
molar mass of Zn = 65.38 g/mol
Step 5: Calculate the mass of zinc required using the moles of zinc and its molar mass:
mass of Zn = moles of Zn * molar mass of Zn
mass of Zn = 0.05 moles * 65.38 g/mol
Therefore, the mass of zinc required to react completely with 100 cm3 of a 1.0M HCl solution is approximately 3.27 grams.
To determine the mass of zinc (Zn) required to react completely with 100 cm3 of 1.0 M hydrochloric acid (HCl), we will use the stoichiometry and balanced chemical equation of the reaction between zinc and hydrochloric acid.
The balanced equation for the reaction is:
Zn + 2HCl -> ZnCl2 + H2
From the equation, we can see that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of zinc chloride and one mole of hydrogen gas.
Firstly, let's calculate the number of moles of HCl present in 100 cm3 of 1.0 M HCl solution.
Given:
Volume of HCl solution = 100 cm3
Molarity of HCl solution = 1.0 M
Moles of HCl = Molarity * Volume (in liters)
= 1.0 mol/L * (100 cm3 / 1000 cm3/L)
= 0.1 mol
According to the stoichiometry of the balanced equation, one mole of zinc reacts with two moles of HCl. Therefore, we need half the number of moles of zinc to react completely.
Moles of Zn = (0.1 mol HCl) / 2
= 0.05 mol
Finally, we need to calculate the mass of zinc using its molar mass.
The molar mass of zinc (Zn) is approximately 65.38 g/mol.
Mass of Zn = Moles of Zn * Molar mass of Zn
= 0.05 mol * 65.38 g/mol
= 3.27 g
Therefore, approximately 3.27 grams of zinc will be required to react completely with 100 cm3 of 1.0 M HCl solution.
Zn + 2HCl ==> H2 + ZnCl2
mols HCl used = M x L = ?
Using the coefficients in the balanced equation, convert mols HCl to mols Zn.
Then mols Zn = grams Zn/atomic mass Zn. You know atomic mass and mols Zn, solve for grams Zn.
Zn + 2 HCl ---> ZnCl₂ + H₂
so .1 moles of HCl reacts with .05 moles of Zn
molar mass of Zn is 65.38 g
.05 * 65.38 = ?