what is the distance between points (-3.2) and (5,-6) express to the nearest tenth?
Make an effort to memorize the distance between two points formula
D = √( (change in x's)^2 + (change in y's)^2 )
= √( (5+3)^2 + (-6-2)^2)
= ...
5.1
To find the distance between two points, we can use the distance formula. The distance formula calculates the distance between two points (x1, y1) and (x2, y2) in a coordinate plane.
The distance formula is given by:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the points are (-3, 2) and (5, -6), so we have:
x1 = -3
y1 = 2
x2 = 5
y2 = -6
Now, we can substitute these values into the distance formula:
distance = √((5 - (-3))^2 + (-6 - 2)^2)
= √(8^2 + (-8)^2)
= √(64 + 64)
= √128
≈ 11.3 (rounded to the nearest tenth)
Therefore, the distance between the points (-3, 2) and (5, -6) is approximately 11.3 units, rounded to the nearest tenth.