if theres a perimeter of 28 and an area of 24 what is length and width
12 and 2
a= l x w 12 x2 = 24
perimeter add all sides
12+ 12 +2 +2 = 28
Factors of 24:
2 * 12
3 * 8
4 * 6
Which of those will give a perimeter of 28?
"Anonymous" shared this with me cuz I was having trouble. Tried 6*4, 8*3, even tried 7*4 (even tho doesn't work)! I FINALLY got my work done after like 50 mins.
2L + 2W = 28.
Divide both sides by 2:
Eq1: L + W = 14.
Eq2: L*W = 24.
L = 24/W.
In Eq1, replace L with 24/W:
24/W + W = 14.
Multiply both sides by W:
W^2 + 24 = 14W.
W^2 - 14W + 24 = 0.
24 = -2*-12, -2 + -12 = -14 = B.
(w-2)(w-12) = 0.
w-2 = 0, W = 2.
w-12 = 0, W = 12.
(L,W)
(12,2)
(2,12)
THANK YOU!!! I forgot that 12 . 2 were factors of 24 (Lol!). I was so thankful that this popped up!
to make it easy
L + w = 14
l w = 24