susan makes $5 per hour babysitting and $7 per hour as a lifegaurd. her goal is to at least $140. which of the following represents three possible solutions to the problem ?
5x+7y ≥ 140
Heyoo-
the answer is 5x+7y>=140 , or option A ! <3
its (A)
@sue plz help
what is the answer?
Well, Susan could babysit for 0 hours and lifeguard for 20 hours (5(0) + 7(20) = 140).
Or she could babysit for 10 hours and lifeguard for 10 hours (5(10) + 7(10) = 140).
Alternatively, Susan could babysit for 20 hours and not lifeguard at all (5(20) + 7(0) = 140).
Remember, "life" can sometimes guard us against financial woes, but it's always good to have a backup plan.
To find possible solutions to the problem, we need to determine the number of hours Susan can work as a babysitter (represented by x) and the number of hours she can work as a lifeguard (represented by y) so that she can earn at least $140.
Let's start by examining the given inequality equation: 5x + 7y ≥ 140
To find three possible solutions, we can substitute different values for x and y that satisfy the inequality.
Solution 1: Let's assume Susan works 0 hours as a babysitter (x = 0) and 20 hours as a lifeguard (y = 20).
Substituting these values into the inequality: 5(0) + 7(20) ≥ 140
0 + 140 ≥ 140
140 ≥ 140
Since 140 is equal to 140, this solution is valid.
Solution 2: Now, let's assume Susan works 10 hours as a babysitter (x = 10) and 10 hours as a lifeguard (y = 10).
Substituting these values into the inequality: 5(10) + 7(10) ≥ 140
50 + 70 ≥ 140
120 ≥ 140
Since 120 is less than 140, this solution is not valid.
Solution 3: Finally, let's assume Susan works 20 hours as a babysitter (x = 20) and 0 hours as a lifeguard (y = 0).
Substituting these values into the inequality: 5(20) + 7(0) ≥ 140
100 + 0 ≥ 140
100 ≥ 140
Since 100 is less than 140, this solution is not valid.
So, the first solution (x = 0, y = 20) represents one possible valid solution to the problem.