Shawn rides his bicycle 9/10 mile to school. On his way to school, he stops at Mike's house, which is 1/5 mile from Shawn's house. Then they both ride to José house, which is 2/7 mile from Mike's house. How far is it from Jose's house to the school?
29/70 can not be reduced its already in its simplest form
To find the distance from Jose's house to the school, we need to add up the distances that Shawn travels.
First, Shawn rides his bicycle 9/10 mile to school. Then, he stops at Mike's house, which is 1/5 mile from Shawn's house. Finally, they both ride to Jose's house, which is 2/7 mile from Mike's house.
We can add these fractions by finding a common denominator. The least common multiple of 10, 5, and 7 is 70. We can then convert each fraction to have a denominator of 70.
For Shawn's ride to school: 9/10 mile * (7/7) = 63/70 mile.
For the distance between Shawn's and Mike's house: 1/5 mile * (14/14) = 14/70 mile.
For the distance between Mike's and Jose's house: 2/7 mile * (10/10) = 20/70 mile.
Now, let's add up the distances:
63/70 mile + 14/70 mile + 20/70 mile = 97/70 mile.
So, the distance from Jose's house to the school is 97/70 mile.
1/5 + 2/7 + x = 9/10
Hint: common denominator is 70
Okay the total distance from shawn's house to school is 9/10
then to Mike 1/5
then to Jose 2/7
you will have to find the common denominator which in this case will be 70
So 9/10 becomes 63/70
1/5 becomes 14/70
then 2/7 becomes 20/70
so the total distance to Jose's house is 14/70 +20/70 = 34/70
now find whats left to travel
63/70-34/70=29/70