The perimeter of the rectangle is 56m the width is 4m less than the length. Find the length and the width of the triangle.
If the length is x, then the width is x-4. So, the perimeter is
2(x + x-4) = 56
To find the length and width of the rectangle, we can start by setting up the given information as equations. Let's assume the length of the rectangle is "L" meters and the width is "W" meters.
1. The perimeter of a rectangle is given by the formula: Perimeter = 2 * (Length + Width)
Therefore, we can write the equation: 2 * (L + W) = 56
2. It is given that the width is 4 meters less than the length, which can be expressed as: W = L - 4
Now, we can use these equations to solve for the length and width of the rectangle.
Let's substitute equation 2 into equation 1:
2 * (L + (L - 4)) = 56
Simplifying the equation:
2 * (2L - 4) = 56
4L - 8 = 56
4L = 56 + 8
4L = 64
L = 64 / 4
L = 16
Now, substitute the value of L back into equation 2 to find the width:
W = L - 4
W = 16 - 4
W = 12
So, the length of the rectangle is 16 meters and the width is 12 meters.