Gary owns a car dealership that sells cars, SUVs and minivans. Gary has three times as
many SUVs as Minivans. He has eight more cars than SUVs. If he has a total of 127 vehicles on
his lot, how many of each type does he have?
59 cars
17 minivans
51 SUVs
To solve this problem, we can set up a system of equations.
Let's use the variables:
C = number of cars
S = number of SUVs
M = number of minivans
Based on the given information, we can write the following equations:
1. Gary has three times as many SUVs as minivans:
S = 3M
2. Gary has eight more cars than SUVs:
C = S + 8
3. The total number of vehicles on the lot is 127:
C + S + M = 127
Now we can solve these equations to find the values of C, S, and M.
Substitute equation 1 into equation 2:
C = (3M) + 8
Substitute equations 1 and 2 into equation 3:
(3M) + 8 + (3M) + M = 127
7M + 8 = 127
7M = 127 - 8
7M = 119
M = 119/7
M = 17
Substitute the value of M back into equation 1:
S = 3(17)
S = 51
Substitute the values of S and M into equation 2:
C = 51 + 8
C = 59
Therefore, Gary has 59 cars, 51 SUVs, and 17 minivans.
Steve and I showed you how to solve this kind of problem.
Try to solve it yourself. We'll be glad to help you then.