A sample of gas has a volume of 12.0 L and a pressure of 20kPa. If the pressure of gas is increased to 50 psi, what is the new volume of the gas?
Vf = 6.96 L
no. Right digits, wrong decimal.
nehi pata
To find the new volume of the gas, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when temperature is held constant.
Boyle's Law can be mathematically expressed as: P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
Given:
P1 = 20 kPa (kilopascals)
V1 = 12.0 L (liters)
P2 = 50 psi (pounds per square inch)
First, let's convert the final pressure from psi to kilopascals. Since 1 psi is approximately equal to 6.895 kPa, we can calculate:
P2 = 50 psi * 6.895 kPa/psi ≈ 344.75 kPa
Now we can plug in the values into Boyle's Law equation and solve for V2:
20 kPa * 12.0 L = 344.75 kPa * V2
Rearranging the equation to solve for V2:
V2 = (20 kPa * 12.0 L) / 344.75 kPa
Calculating the result:
V2 ≈ 0.690 L
Therefore, the new volume of the gas is approximately 0.690 L.