what is the value of the range of the function f(x)=x^2+2 for the domain value 1/4?
How do I solve? Please don't just straight up give me the answer >.< I want to know how to do this.
f(x) maps vales in the domain to values in the range, using the given rule. So, to find f(1/4), replace all the x's with 1/4:
f(1/4) = 2(1/4)^2 + 2
Now just simplify that.
To find the value of the function f(x) = x^2 + 2 for the domain value 1/4, we'll follow these steps:
Step 1: Substitute the domain value into the function.
To find f(1/4), substitute x with 1/4 in the function:
f(1/4) = (1/4)^2 + 2
Step 2: Simplify the expression.
Evaluate (1/4)^2, which is equal to 1/16:
f(1/4) = 1/16 + 2
Step 3: Add the fractions.
Find a common denominator for 1/16 and 2, which is 16. Multiply 2 by 16/16 to make it have a denominator of 16:
f(1/4) = 1/16 + 2*(16/16)
f(1/4) = 1/16 + 32/16
Step 4: Simplify the expression.
Add the fractions with a common denominator:
f(1/4) = (1 + 32)/16
f(1/4) = 33/16
So, the value of the function f(x) = x^2 + 2 for the domain value 1/4 is 33/16.