2 NO + 2 SO2 → 1 N2 + 2 SO3
Determine the mass (in g) of N2 that would be produced when 5.28×10-3 g of SO2 reacts with an excess of NO.
To determine the mass of N2 produced, we need to use the given balanced chemical equation and the molar masses of SO2 and N2.
1. Write down the balanced equation:
2 NO + 2 SO2 → 1 N2 + 2 SO3
2. Find the molar mass of SO2:
The molar mass of SO2 is 2 * atomic mass of sulfur (S) + 2 * atomic mass of oxygen (O).
Sulfur (S) has an atomic mass of 32.06 g/mol, and oxygen (O) has an atomic mass of 16.00 g/mol.
Molar mass of SO2 = 2 * 32.06 g/mol + 2 * 16.00 g/mol = 64.12 g/mol + 32.00 g/mol = 96.12 g/mol
3. Convert the given mass of SO2 to moles:
Using the molar mass of SO2, we can calculate the number of moles.
moles of SO2 = mass of SO2 / molar mass of SO2
moles of SO2 = 5.28 × 10^(-3) g / 96.12 g/mol
4. Calculate the moles of N2 produced:
From the balanced equation, we can see that 2 moles of SO2 produce 1 mole of N2.
Therefore, moles of N2 = 1/2 * moles of SO2
5. Convert moles of N2 to grams:
Using the molar mass of N2, we can calculate the mass of N2 produced.
Molar mass of N2 = 14.01 g/mol
mass of N2 = moles of N2 * molar mass of N2
Now, let's substitute the values into the equations:
moles of SO2 = 5.28 × 10^(-3) g / 96.12 g/mol
moles of N2 = 1/2 * moles of SO2
mass of N2 = moles of N2 * molar mass of N2
mass of N2 = (1/2 * 5.28 × 10^(-3) g / 96.12 g/mol) * 14.01 g/mol
Calculate to get the final answer for the mass of N2 produced.
To determine the mass of N2 produced, we first need to calculate the number of moles of SO2 present in the given mass.
1. Calculate the molar mass of SO2 (sulfur dioxide):
Molar mass of S = 32.07 g/mol
Molar mass of O = 16.00 g/mol (x2 in SO2)
Molar mass of SO2 = 32.07 g/mol + 16.00 g/mol (x2) = 64.07 g/mol
2. Calculate the number of moles of SO2:
Moles of SO2 = mass of SO2 / molar mass of SO2
Moles of SO2 = 5.28×10-3 g / 64.07 g/mol
Next, we need to use the balanced chemical equation to determine the stoichiometric ratio between SO2 and N2.
The balanced chemical equation is:
2 NO + 2 SO2 → 1 N2 + 2 SO3
From the equation, we can see that 2 moles of SO2 react to form 1 mole of N2.
3. Calculate the number of moles of N2 produced:
Moles of N2 = (moles of SO2) x (moles of N2 / moles of SO2)
Moles of N2 = (5.28×10-3 g / 64.07 g/mol) x (1 mol N2 / 2 mol SO2)
Finally, we can calculate the mass of N2 produced by multiplying the number of moles of N2 by its molar mass.
4. Calculate the mass of N2:
Mass of N2 = moles of N2 x molar mass of N2
Mass of N2 = (5.28×10-3 g / 64.07 g/mol) x (1 mol N2 / 2 mol SO2) x molar mass of N2
You can substitute the molar mass of N2 (28.01 g/mol) and perform the calculations to find the mass of N2 produced.