Chemistry

posted by Brian

How many ml of water must be added to 40.0 ml of 2.50 m koh to prepare a solution that is 0.212 m?

  1. DrBob222

    Do you know that M and m are not the same thing? Which do you want?

  2. Brian

    Apologies, the numbers corrected are: 40.0 ml of 2.50 M KOH to prep a solution that is 0.212 M

  3. DrBob222

    mL1 x M1 = mL2 x M2
    x*0.212M = 40*2.5
    Solve for x and that is the TOTAK volume required. Total-40 is what must be added.

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