posted by Brian
How many ml of water must be added to 40.0 ml of 2.50 m koh to prepare a solution that is 0.212 m?
Do you know that M and m are not the same thing? Which do you want?
Apologies, the numbers corrected are: 40.0 ml of 2.50 M KOH to prep a solution that is 0.212 M
mL1 x M1 = mL2 x M2
x*0.212M = 40*2.5
Solve for x and that is the TOTAK volume required. Total-40 is what must be added.