Simultaneous equation
posted by Collins .
X+y+z=1......(1)
x^2+y^2+z^2=35........(2)
x^3+y^3+z^3=97.........(3)
solution but from 3
(x^3+y^3)=(x+y)^33xy(x+y)......(4)
puting 4 into 3 bck
(x+y)^33xy(x+y)+z^3=97.......(5)
now from 1
x+y=1z......(6)
putin 6 into 7 we have
(1z)^33xy(1z)+z^3=97
[12z+z^2](1z)3xy(1z)+z^3=97
1(12z+z^2)z(12z+z^2)3xy(1z)+z^3=97
12z+z^2z+2z^2z^33xy(1z)+z^3=97
3z^23zz3xy(1z)=96
3z^24z3xy(1z)=96........(8)
but from 2
(x^2+y^2)=(x+y)^22xy.........(9)
putin 9 bck to 2
(x+y)^2xy+z^2=35......(10)
puting 6 into 10
(1z)^2xy+z^2=35
[12z+z^2)2xy+z^2=35
2z^22z2xy=34
z^2zxy=17
xy=17z^2z
xy=17z^2+z
xy=17+z^2z
xy=z^2z17
putin xy into8
3z^23zz3(z^2z17)(1z)=96
3z^24z3(z^2z17)(1z)=96....plz help me finish it

It is 
Collins
Plz it is 3z not 4z

Simultaneous equation 
Steve
well, if we want integer solutions, it is clear that not all the values can be positive. However, squares are positive, and we know that
1^2+3^2+5^2 = 35
You will need to make one or two of the variables negative, so you sum to 1, but that should work for the cubes as well. 
Simultaneous equation 
Collins
Steve can u please just interpret what you are saying for me please..so that i can continue

Simultaneous equation 
Steve
well, using the values 1,3,5
how can you make them add up to 1 if not all are positive? 
Simultaneous equation 
Collins
Yez i got that steve thanks so much wish to be like you someday
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