You are preparing 500 mL of Denaturation Buffer containing 1.5 M NaCl and 0.5 M NaOH. Your stock solutions are 5 M NaCl and 6 M NaOH. How would you prepare the Denaturation Buffer? Include all of the solutions needed to make the buffer.
For Nacl, C1V1=C2V2
5*V1=500*1.5
V1=150 ml of Nacl
For NaoH,
6*V1=500*0.5
V1=41.6 ml of NaoH
Is that correct?
Your calculations are correct, but there is a slight mistake in the second calculation for NaOH.
For NaCl:
C1V1 = C2V2
5 * V1 = 500 * 1.5
V1 = (500 * 1.5) / 5
V1 = 150 mL of NaCl stock solution
For NaOH:
C1V1 = C2V2
6 * V1 = 500 * 0.5
V1 = (500 * 0.5) / 6
V1 â 41.67 mL of NaOH stock solution (approximately 41.7 mL)
Therefore, to prepare the Denaturation Buffer, you will need approximately 150 mL of 5 M NaCl stock solution and approximately 41.7 mL of 6 M NaOH stock solution.
Yes, your calculations for preparing the Denaturation Buffer are correct. To prepare 500 mL of Denaturation Buffer containing 1.5 M NaCl and 0.5 M NaOH, you would need the following solutions:
1. 150 mL of 5 M NaCl stock solution: Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (5 M), V1 is the volume of the stock solution you need to add, C2 is the final desired concentration (1.5 M), and V2 is the final volume of the buffer solution (500 mL). Plugging in the values, you would calculate the volume of the 5 M NaCl stock solution to be 150 mL.
2. 41.6 mL of 6 M NaOH stock solution: Again, use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (6 M), V1 is the volume of the stock solution you need to add, C2 is the final desired concentration (0.5 M), and V2 is the final volume of the buffer solution (500 mL). Plugging in the values, you would calculate the volume of the 6 M NaOH stock solution to be approximately 41.6 mL.
Therefore, to prepare the Denaturation Buffer, you would need to add 150 mL of 5 M NaCl stock solution and approximately 41.6 mL of 6 M NaOH stock solution to a total volume of 500 mL.