Write the dissociation equation for iron(II) ammonium sulfate hexahydrate in water .

Fe(NH4)2(SO4)2 * 6H2O --> __?________

I know dissociate means to take apart so for example; NaCl would look like Na^+ + Cl^-
And another one like: Fe2(SO4)3 would look like 2Fe^+3 + 3SO4^-2 but I can't seem to figure out how (the question above) would look like when it is dissociated. Can you please explain step by step on how to get the answer for my problem? Thank you so much! All help needed!

Fe(NH4)2(SO4)2 * 6H2O does not dissociate completely in water. However, we can write an equation to show the partial dissociation:

Fe(NH4)2(SO4)2 * 6H2O ⇌ Fe2+ + 2NH4+ + 2SO42- + 6H2O

In this equation, Fe(NH4)2(SO4)2 * 6H2O breaks apart into Fe2+ ions, 2 NH4+ ions, 2 SO42- ions, and 6 water molecules. However, it is important to note that this is a partial dissociation, meaning not all of the compound will dissociate. The extent of the dissociation depends on the concentration of the solution and other factors.

To write the dissociation equation for iron(II) ammonium sulfate hexahydrate (Fe(NH4)2(SO4)2 * 6H2O) in water, we need to break apart each ion into its component parts.

Step 1: Write the formula for the compound:
Fe(NH4)2(SO4)2 * 6H2O

Step 2: Identify the ions present in the compound. The compound contains iron(II) cations (Fe^2+), ammonium cations (NH4^+), sulfate anions (SO4^2-), and water molecules (H2O).

Step 3: Break apart the compound into its ions:
Fe(NH4)2(SO4)2 * 6H2O → Fe^2+ + 2NH4^+ + 2SO4^2- + 6H2O

So, the dissociation equation for iron(II) ammonium sulfate hexahydrate in water is:
Fe(NH4)2(SO4)2 * 6H2O → Fe^2+ + 2NH4^+ + 2SO4^2- + 6H2O

To write the dissociation equation for iron(II) ammonium sulfate hexahydrate, you need to separate the compound into its constituent ions. Here's a step-by-step guide on how to do it:

Step 1: Identify the compound and its formula.
The compound in question is iron(II) ammonium sulfate hexahydrate, which has the chemical formula Fe(NH4)2(SO4)2 * 6H2O.

Step 2: Understand the composition of the compound.
This compound consists of iron(II) ions (Fe^2+), ammonium ions (NH4^+), sulfate ions (SO4^2-), and water molecules (H2O).

Step 3: Determine the number of each ion present in the compound.
From the compound's formula, you can see that there is one iron(II) ion (Fe^2+), two ammonium ions (NH4^+), two sulfate ions (SO4^2-), and six water molecules (H2O) present.

Step 4: Write the dissociation equation.
Now that we know the composition of the compound, we can write its dissociation equation by separating the ions:

Fe(NH4)2(SO4)2 * 6H2O --> Fe^2+ + 2NH4^+ + 2SO4^2- + 6H2O

The dissociation equation shows that when iron(II) ammonium sulfate hexahydrate is dissolved in water, it breaks apart into its respective ions: one iron(II) ion (Fe^2+), two ammonium ions (NH4^+), two sulfate ions (SO4^2-), and six water molecules (H2O).

Please note that in the dissociation equation, the charge of each ion is indicated as a superscript after the element or group symbol (e.g., Fe^2+, NH4^+, SO4^2-).

I don't get your problem. You know exactly how to handle NaCl and Fe2(SO4)3, why not do Fe(NH4)2(SO4)2 the same way.

Fe^2+ + 2NH4^+ + 2SO4^2-