Probability license Arrangements
posted by Amber .
All license plates have a letter, two characters (which are either a number or a letter) Followed by two numbers. The letter choice for the first character can only be either an E,W,P,R,A,F OR U. How many license plates can be made? What is the probability of having one with a vowel?

Probability license Arrangements 
Reiny
so a possible valid choice could be R 2S 56
All cases = 7 x 36 x 36 x 10 x 10907200
Assuming 5 vowels
number of cases without a vowel
= 4 x 31 x 31 x 10 x 10 = 3844400
prob(of having a vowel) = 1  384400/1090700
= appr .576
check my arithmetic 
Probability license Arrangements 
Reiny
Found a typo .... forgot the = sign
should be :
All cases = 7 x 36 x 36 x 10 x 10 = 907200
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