Write potassium sulphate +barium nitrate �¨ potassium nitrate + barium sulphate as a balanced symbol equation
K2SO4 + Ba(NO3)2 ==> 2KNO3 + BaSO4
Thanks
No problem boblem
To balance the symbol equation, we need to ensure that the number and type of atoms on both sides of the equation are the same. Here's how you can do it:
1. Write the chemical formula for each compound:
- Potassium sulphate: K2SO4
- Barium nitrate: Ba(NO3)2
- Potassium nitrate: KNO3
- Barium sulphate: BaSO4
2. Identify the elements present in the compounds:
- Potassium (K)
- Sulphur (S)
- Oxygen (O)
- Barium (Ba)
- Nitrogen (N)
3. Count the number of atoms for each element on both sides of the equation:
Potassium sulphate: 2K + 1S + 4O
Barium nitrate: 1Ba + 2N + 6O
Potassium nitrate: 1K + 1N + 3O
Barium sulphate: 1Ba + 1S + 4O
4. Now, you can begin balancing the equation by adjusting coefficient numbers in front of each compound. Start with the elements that appear in the fewest compounds, and work your way up:
- Balancing potassium (K):
On the left side, there are already 2K in potassium sulphate, so place a 2 in front of potassium nitrate:
K2SO4 + Ba(NO3)2 → 2KNO3 + BaSO4
- Balancing barium (Ba):
On the right side, there is already 1Ba in barium sulphate, so there is no need to adjust the coefficient for barium nitrate:
K2SO4 + Ba(NO3)2 → 2KNO3 + BaSO4
- Balancing sulphur (S):
On the left side, there is already 1S in potassium sulphate, so there is no need to adjust the coefficient for barium sulphate:
K2SO4 + Ba(NO3)2 → 2KNO3 + BaSO4
- Balancing nitrogen (N):
On the left side, there are 2N in barium nitrate, so place a 2 in front of potassium nitrate:
K2SO4 + Ba(NO3)2 → 2KNO3 + BaSO4
- Balancing oxygen (O):
On the left side, there are 4O in potassium sulphate, so place a 4 in front of barium nitrate:
K2SO4 + 4Ba(NO3)2 → 2KNO3 + BaSO4
Finally, the balanced symbol equation is:
K2SO4 + 4Ba(NO3)2 → 2KNO3 + BaSO4