Calculate the mass of anhydrous sodium carbonate Na2Co3 required to prepare 2.5 litres of 0.50M aqueous solution.(Na=23,C=12,O=16)
How many mols do you want? That's mols = M x L = ?
How many grams is that. grams = mols x molar mass = ?
Moles=concentration x Volume (n=cv)
0.5 x 250 divided by 1000
0.5/1 x 250/1000= 0.125
Calculate the Molar MAss of anhydrous Calcium Carbonate
Na2 = (2 x 22.98) + C (1 x 12.01) + O3 (3 x 15.99) = 105.987 g/Mol
m (MASS)= 0.125 x 105.987 = 13.248 g
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To calculate the mass of anhydrous sodium carbonate (Na2CO3) required to prepare a 0.50M aqueous solution, you will need to use the formula:
Mass = Molarity x Volume x Molecular Weight
Step 1: Calculate the molecular weight of anhydrous sodium carbonate (Na2CO3):
Na2CO3 = (2 x Na) + C + (3 x O)
= (2 x 23) + 12 + (3 x 16)
= 46 + 12 + 48
= 106 g/mol
Step 2: Convert the 2.5 liters of solution to milliliters (mL):
1 liter = 1000 mL
2.5 liters = 2.5 x 1000 mL
2.5 liters = 2500 mL
Step 3: Calculate the mass of anhydrous sodium carbonate:
Mass = 0.50M x 2500 mL x 106 g/mol
Mass = 0.50 x 2500 x 106
Mass = 132500 g
Therefore, the mass of anhydrous sodium carbonate required to prepare 2.5 liters of 0.50M aqueous solution is 132500 grams.