Write the formulas of the compounds formed by Pb4+ with the following anions: NO3−, HCO3−, SO42−, H2PO4
I passed up a similar question a couple of days ago and it may have been posted by you. My problem is I'm not sure some of those compounds in the previous post or compounds in this post even exist. If these are hypothetical formulas I can help; otherwise, please explain where these came from and the purpose of the question. It would help, too, if you explained what your problem is in answering the question.
The formulas of the compounds formed by Pb4+ with the given anions are as follows:
1. With NO3− (nitrate):
- Pb(NO3)4
2. With HCO3− (bicarbonate):
- Pb(HCO3)4
3. With SO42− (sulfate):
- Pb(SO4)4
4. With H2PO4− (dihydrogen phosphate):
- Pb(H2PO4)4
To determine the formulas of compounds formed by Pb4+ with different anions, you need to consider the charges of both the cation (Pb4+) and the anions (NO3−, HCO3−, SO42−, H2PO4−), and then balance the charges to create a neutral compound.
1. Lead(IV) Nitrate: Pb4+ with NO3−
The charge of NO3− is -1. Since Pb4+ is a cation with a charge of +4, you will need four NO3− ions to balance the charge. Therefore, the formula for Lead(IV) Nitrate is Pb(NO3)4.
2. Lead(IV) Bicarbonate: Pb4+ with HCO3−
The charge of HCO3− is -1. Since Pb4+ is a cation with a charge of +4, you will need four HCO3− ions to balance the charge. However, bicarbonate is a polyatomic ion, and it is more common to write polyatomic ions with brackets in the formula. Therefore, the formula for Lead(IV) Bicarbonate is Pb(HCO3)4.
3. Lead(IV) Sulfate: Pb4+ with SO42−
The charge of SO42− is -2. Since Pb4+ is a cation with a charge of +4, you will need two SO42− ions to balance the charge. Therefore, the formula for Lead(IV) Sulfate is Pb(SO4)2.
4. Lead(IV) Dihydrogen Phosphate: Pb4+ with H2PO4−
The charge of H2PO4− is -1. Since Pb4+ is a cation with a charge of +4, you will need four H2PO4− ions to balance the charge. However, phosphate is a polyatomic ion, and it is more common to write polyatomic ions with brackets in the formula. Therefore, the formula for Lead(IV) Dihydrogen Phosphate is Pb(H2PO4)4.
Remember to always balance the charges of the cation and anion to create a neutral compound.