Logarithm help
posted by Joe
using logarithms to solve exponential equations.
5^1+x = 2^1x
I need exact numbers.
I did one on my own already. 5^x1 = 9
5^x1 = 9
log(5^x1) = log9
(log5)(x1) = log9
x1 = (log9/log5)
x= (log9/log5)1
x = 2.3652
Logarithm help  Joe, Friday, September 18, 2015 at 10:55pm
I really need help
Logarithm help  Savio, Friday, September 18, 2015 at 11:13pm
log(5^(1+x))= log(2^(1x))
(1+x)(log 5)= (1x)(log 2)
(x+1)/(x1)=.4306765581
x+1= .4306765581x.4306765581
At this point it's a simple algebraic solution to solve for x. :)
Logarithm help  Joe, Friday, September 18, 2015 at 11:27pm
The answer in the textbook says 0.398. I don't think the answer above gives me 0.398.
Logarithm help  Steve, Saturday, September 19, 2015 at 12:27am
(1+x)(log 5)= (1x)(log 2)
(1+x)/(1x) = log2/log5 = .4306765581
x = 0.39794
That doesn't make sense. How can you jump from 0.43067 to 0.39794?

Steve
come on  simple algebra:
(1+x)/(1x) = .4306765581
1+x = .4306765581(1x)
Think you can handle it now?
How about 1+x = 3(1x)
Respond to this Question
Similar Questions

logarithms
5^x=5^6 Take the log base 5 of each side: log5 5^x=log5 5^6 x= 6 is your teacher Mrs. Lake? 
Logs.
Can you please help me with the following log. problems? 
algebra
Solve for x 1. log5 X=3 2. Log2 16log2 =x 3. Log9 6561=x 
math
Algebraically determine the value(s) of x: log9(x5)=1log9(x+3) Please help me. Thanks! 
Algebra 2
Express as a logarithm of a single number or expression: 1. 5log4^p+log4^q 2. log10^x4 log10^y 3. 4log3^A1/2 log3^B 4. log5^M+1/4 log5^N 5. log2^M+log2^N+3 6. log5^xlog5^y+2 7. 13 log5^x 8. (1+log9^x)/2 I need to see all of the … 
precalculus
solve the logarithmic equation . express solution in exact form log5(x9)+log5(x+4)=1+log5(x5) 
math
Which logarithmic equation is equivalent to the exponential equation below? 
Logarithm help
using logarithms to solve exponential equations. 5^1+x = 2^1x I need exact numbers. I did one on my own already. 5^x1 = 9 5^x1 = 9 log(5^x1) = log9 (log5)(x1) = log9 x1 = (log9/log5) x= (log9/log5)1 x = 2.3652 
Math
Logarithms 3^x2=18 Work log(3^x2)=log18 (x2)log3=log18 xlog32log3=log18 x=log3/(log9log18) e^3x+1=10 lne^3x+1=ln10 3x+1=ln10 I'm stuck here 8^x=5^2x1 xlog8=(2x1)log5 xlog8=2xlog5log5 x=log10/(log5log8) Are these right? 
Math
Simplify (Log75+log9+log5)รท(log5+log45)