Train #1 leaves san diego at 4pm. train #2 leaves san diego at 6pm.train #2 travels 42 mph faster than train #1. if train # 2 overtakes train #1 at 8pm, what is the speed of each train?
since distance = speed * time,
If train #1's speed is x,
4x = 2(x+42)
FOUR BEADS FOR 16 SENT I PAY 1 DOLLAR HOW MUCH DO I GET BACK
To find the speeds of these two trains, let's break down the information given and apply some mathematical reasoning.
1. Train #1 departs from San Diego at 4 PM, and train #2 departs at 6 PM. This means train #1 has a two-hour head start.
2. Train #2 overtakes train #1 at 8 PM, which implies they meet after traveling for 2 hours.
3. It is also given that train #2 travels 42 mph faster than train #1.
Let's denote the speed of train #1 as x mph.
Since train #2 travels 42 mph faster than train #1, the speed of train #2 can be expressed as (x + 42) mph.
Now, let's determine the distances covered by each train during the 2-hour interval:
Distance covered by train #1 = speed * time
Distance covered by train #1 = x mph * 2 hours = 2x miles
Distance covered by train #2 = speed * time
Distance covered by train #2 = (x + 42) mph * 2 hours = 2(x + 42) miles
Since train #2 overtakes train #1, the distances covered by both trains must be equal:
2x = 2(x + 42)
2x = 2x + 84
By subtracting 2x from both sides, we get:
0 = 84
This is a contradiction where the equation becomes illogical. It means that such a scenario cannot occur with the given information. Hence, there is no valid solution for the speeds of train #1 and train #2 based on the provided details.