A circle has a center at (8,2). The point is (3,7) is on the circle. What is the area of the circle to the nearest tenth of a square unit?

A. 22.2
B. 44.4
C. 157.1
D. 314.2
(I've been stuck on this question for a while) thanks!!

The circle is

(x-8)^2 + (y-2)^2 = r^2
Plug in your point (3,7) and you have

(3-8)^2 + (7-2)^2 = r^2
Now that you have r^2, you know the area is just pi r^2

I still don't get the answer steve? I calculated, but nothing close.

Hmmm. Let's see.

r^2 = 5^2+5^2 = 50
The area is πr^2, or 50*3.14159 = 157.09

Looks like C to me.

If you try stuff and it seems wrong, you really should post your work, so we can help fix it.

To find the area of a circle, we need its radius.

The distance between the center of the circle, at (8,2), and the point on the circle, at (3,7), is the radius of the circle.

We can use the distance formula to find the distance between two points:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)

In this case, the distance between the two points is:
Distance = √((3 - 8)^2 + (7 - 2)^2)
= √((-5)^2 + (5)^2)
= √(25 + 25)
= √50
= 5√2

Now we have the radius of the circle, which is 5√2.

To find the area of the circle, we use the formula:
Area = π * (radius)^2

Substituting the value of the radius, we get:
Area = π * (5√2)^2
= π * 25 * 2
= 50π

Now, we can calculate the approximate value of the area of the circle:

Using π ≈ 3.14, we get:
Area ≈ 50 * 3.14
≈ 157

Therefore, the area of the circle to the nearest tenth of a square unit is approximately 157.1 square units.

So the correct answer is C. 157.1.