a car moving at 6m/s accelerate at 1.5meter squared per second for 4seconds.It then it slows down at rate 1.2 meter squared per second. What is the distance travel?
V = Vo + a*t = 6 + 1.5*4 = 12 m/s.
d1 = Vo*t + 0.5*a*t^2=6*4 + 0.5*1.5*4^2 =
24 + 12 = 36 m.
d2 = (V^2-Vo^2)/2a = (0-144)/-2.4=60 m.
d = d1+d2 = 36 + 60 96 m.