posted by G
A bar 4.0 m long weighs 400. N. Its center of gravity is 1.5 m from one end. A weight of 300. N is attached at the heavy end and a weight of 500. N is attached at the light end. What are the magnitude, direction, and point of application of the force needed to achieve translational and rotational equilibrium of the bar?
please help! the answer is 2.17 m from pivot end or 1.84 m from other end. but i don't know the process or how to solve!help is much appreciated