You roll a number cube twice. Find P (even, then not 2). Write the probability as a fraction in simplest form. I'm fully clueless to the answer to this question. Can someone please help me out? Thanks Very Much and need the answer A.S.A.P!

?/12

5/12?

Solution:

3/6 * 5*6 = 15/36 = 5/12

Sure! I'll explain how to solve this problem step by step.

To find the probability of rolling an even number first and then not rolling a 2 on a number cube, we need to determine the number of favorable outcomes and the total number of possible outcomes.

Step 1: Determine the number of favorable outcomes.
The possible even numbers on a standard number cube are 2, 4, and 6. However, we want to roll an even number first and then not roll a 2. So, in this case, the only favorable outcome is rolling a 4 or a 6.

Step 2: Determine the total number of possible outcomes.
Since we are rolling the number cube twice, each roll has 6 possible outcomes. Therefore, the total number of possible outcomes is 6 x 6 = 36.

Step 3: Calculate the probability.
To calculate the probability, we divide the number of favorable outcomes (2) by the total number of possible outcomes (36).

So, P(even, then not 2) = 2/36.

To simplify the fraction, we divide both the numerator and denominator by their greatest common divisor, which is 2. Therefore, we get:

P(even, then not 2) = 1/18.

So, the probability of rolling an even number first and then not rolling a 2 on a number cube is 1/18 (in simplest form).