Use the info below to calculate how much it would cost you to produce 500g of NiSO4*6H2O . don't forget to include the cost of the original nickel token .
Na2CO3*H2O costs $6.58/3 kg
6 M H2SO4 costs $12.65/5L
9 M HNO3 costs $10.53/2.5L
Show clearly how you obtained your answer. NiSO4*6H2O sells at $21.70 for 500g . If you could sell 500g of your NiSO4*6H2O for $21.70 what profit would you make?
Here's my data to be used:
Mass of nickel token- 4.49g
Mass of Na2CO3*H2O- 22.50g
Volume of 6 M H2SO4 used- 20ml
Mass of NiSO4*6H2O formed- 12.52g
This is the last question of my lab so please help !!
Do you have the equation(s)? Can you use stoichiometry to calculate the grams NiSO4.6H2O you can produce? Exactly what trouble are you having with this?
I have no idea how to do this like idk I'm really confused with this question..
You must have something in your experiment from which you can get the equations. I can guess what you might do but that isn't good enough. I presume you add Ni to HNO3 to dissolve the metal BUT you're not given any grams HNO3 used. Where does the Na2CO3 come in? What comes after that?
To calculate the cost of producing 500g of NiSO4*6H2O, we need to consider the cost of all the reactants used in the synthesis.
Given information:
- Mass of nickel token: 4.49g
- Mass of Na2CO3*H2O used: 22.50g
- Volume of 6 M H2SO4 used: 20ml
- Mass of NiSO4*6H2O formed: 12.52g
- Cost of Na2CO3*H2O: $6.58/3 kg
- Cost of 6 M H2SO4: $12.65/5L
Step 1: Calculate the cost of Na2CO3*H2O used:
To calculate the cost, we need to find the cost per gram of Na2CO3*H2O.
Cost per gram = (Cost per 3 kg) / 3000
Cost per gram = $6.58 / 3000g
Now, to find the cost of 22.50g Na2CO3*H2O, we multiply the cost per gram by the mass used:
Cost of Na2CO3*H2O used = Cost per gram * Mass used
Step 2: Calculate the cost of 6 M H2SO4 used:
To calculate the cost, we need to find the cost per mL of 6 M H2SO4.
Cost per mL = (Cost per 5L) / 5000
Cost per mL = $12.65 / 5000mL
Now, to find the cost of 20 mL of 6 M H2SO4 used, we multiply the cost per mL by the volume used:
Cost of 6 M H2SO4 used = Cost per mL * Volume used
Step 3: Calculate the total cost of reactants:
Total cost = Cost of Na2CO3*H2O used + Cost of 6 M H2SO4 used + Cost of nickel token
Step 4: Calculate the profit:
Profit = Selling price of NiSO4*6H2O - Total cost
Given:
Selling price of 500g NiSO4*6H2O = $21.70
Let's calculate the costs and profit:
Step 1:
Cost per gram of Na2CO3*H2O = $6.58 / 3000 = $0.00219/g
Cost of Na2CO3*H2O used = $0.00219/g * 22.50g = $0.049275
Step 2:
Cost per mL of 6 M H2SO4 = $12.65 / 5000mL = $0.00253/mL
Cost of 6 M H2SO4 used = $0.00253/mL * 20mL = $0.0506
Step 3:
Total cost = Cost of Na2CO3*H2O used + Cost of 6 M H2SO4 used + Cost of nickel token
Total cost = $0.049275 + $0.0506 + 0 (assuming the cost of nickel token is zero)
Total cost = $0.099875
Step 4:
Profit = Selling price of NiSO4*6H2O - Total cost
Profit = $21.70 - $0.099875
Profit = $21.600125
Therefore, the profit made by selling 500g of NiSO4*6H2O for $21.70 is approximately $21.60.