A triangle with a Base of 8 inches and a height of 7 inches has a circular section of diameter 3 inches removed from its center. What is the remaining area of the triangle? (Use π = 3.14)
Area of triangle:
A = (1/2)bh
Area of circle:
A = (π/4)d^2
The remaining area is therefore,
(1/2)bh - (π/4)d^2
Substituting,
(1/2)(8)(7) - (π/4)(3)^2 = ?
Units in in^2. Hope this helps~ `u`
7 years late but thx
To find the remaining area of the triangle, we need to calculate the area of the triangle and subtract the area of the circular section.
First, let's find the area of the triangle. The formula for the area of a triangle is (base * height) / 2. Plugging in the given values, we have:
Area of the triangle = (base * height) / 2 = (8 inches * 7 inches) / 2 = 56 square inches.
Next, let's find the area of the circular section. The formula for the area of a circle is π * (radius^2), where π is approximately 3.14.
Given that the diameter of the circular section is 3 inches, the radius is half of the diameter, which is 3 inches / 2 = 1.5 inches.
Area of the circular section = π * (radius^2) = 3.14 * (1.5 inches)^2 = 3.14 * 2.25 square inches ≈ 7.065 square inches.
Finally, let's subtract the area of the circular section from the area of the triangle to find the remaining area:
Remaining area = Area of the triangle - Area of the circular section = 56 square inches - 7.065 square inches ≈ 48.935 square inches.
Therefore, the remaining area of the triangle is approximately 48.935 square inches.