posted by Jonathan
What is the change in entropy when 9.30 mL of liquid benzene (C6H6, d = 0.879 g/mL) is burned in the
presence of 37.2 L of oxygen gas, measured at 298 K and 1 atm pressure?
2C6H6(l) + 15O2(g) → 12CO2(g) + 6H2O(l); ∆S° = –437.7 J/K at 298 K
dSrxn = (n*dSo products) - (n*dSo reactants)
Look up the So values in your text/notes. They should be in a table at the end of your text.