A conical drinking cup is made from a circular piece of paper of radius R inches by cutting out a sector and joining the edges CA and CB. Find the radius, height and volume of the cone of greatest volume that can be made this way

The circumference of the original paper is

2πR

If the arc AB subtends an angle θ, then the circumference of the cone formed is

2πR - Rθ = R(2π-θ)

So, the radius of the cone is r = R(1-θ/2π)

Since the slant height of the cone is still r, the the altitude of the cone is

√(R^2 - r^2)

To find the cone of greatest volume that can be made using a circular piece of paper by cutting out a sector and joining the edges CA and CB, we need to determine the radius, height, and volume of the cone.

Let's start by visualizing the problem:

1. Draw a circle representing the circular piece of paper, with radius R inches.
2. Cut out a sector from the circle by removing a portion of it, leaving a smaller circular section.
3. Join the edges CA and CB of the remaining section to form a cone.

We want to find the dimensions of this cone that will maximize its volume.

Let's proceed with the solution step-by-step:

Step 1: Find the central angle of the sector
The central angle of the sector can be calculated by subtracting the apex angle of the cone (2θ) from 360 degrees. Since a full circle measures 360 degrees, the remaining angle forms a sector.

Step 2: Find the slant height of the cone
The slant height of the cone can be determined using the radius (R) and the central angle (θ) of the sector. The formula for the slant height is given by:
slant height (l) = R * sqrt(2 - 2 * cos(θ))

Step 3: Find the radius and height of the cone
Given that AC = AB = l, the radius (r) of the cone is equal to half of AC. The height (h) of the cone can be found by applying the Pythagorean theorem in the right triangle formed by R, r, and the height.

Step 4: Calculate the volume of the cone
The volume (V) of a cone can be determined using the formula:
volume = (1/3) * pi * r^2 * h

Let's summarize the steps as follows:

Step 1: Find the central angle of the sector: θ = 360 - 2θ

Step 2: Find the slant height of the cone: l = R * sqrt(2 - 2 * cos(θ))

Step 3: Find the radius and height of the cone:
r = l / 2
h = sqrt(R^2 - r^2)

Step 4: Calculate the volume of the cone: V = (1/3) * pi * r^2 * h

Please provide the value of θ, and I will calculate the radius, height, and volume of the cone for you.

To find the cone of greatest volume that can be made, we need to optimize the volume with respect to the radius. We can do this by differentiating the volume equation with respect to the radius and equating it to zero.

Let's start by visualizing the problem. We have a circular piece of paper with radius R, and we need to cut out a sector and join the edges CA and CB to form a cone.

The first step is to find the height of the cone. We can do this by using the Pythagorean theorem.

Let AC be the radius of the sector, and let h be the height of the cone. Then, AC^2 = R^2 - (R - h)^2.

Simplifying this equation, we get AC^2 = 2Rh - h^2.

Next, we can find the area of the sector that needs to be cut out. The area of a sector is given by (θ/360) * π * R^2, where θ is the angle of the sector.

Since the length of the entire circumference is 2πR, the length of the sector's arc is (θ/360) * 2πR. This arc length is equal to the length of the circumference of the cone's base, which is 2πr.

Setting these two lengths equal, we get (θ/360) * 2πR = 2πr.

Simplifying this equation, we get r = (θ/360) * R.

Now, we can find the volume of the cone. The volume of a cone is given by V = (1/3) * π * r^2 * h.

Plugging in the value of r from the previous equation and substituting the equation for AC^2, we get V = (1/3) * π * [(θ/360) * R]^2 * (2Rh - h^2).

Now, we differentiate the volume equation with respect to h and set it equal to zero to find the optimal height.

dV/dh = (1/3) * π * [(θ/360) * R]^2 * (2R - 2h) - (1/3) * π * [(θ/360) * R]^2 * (2h) = 0.

Simplifying this equation, we get 2R - 2h - 2h = 0.

Rearranging the equation, we get R = 2h.

Substituting this value of R back into the equation for the height of the cone, we get 2h^2 = 2Rh - h^2.

Substituting R = 2h into this equation, we get 2h^2 = 4h^2 - h^2.

Simplifying this equation, we get h^2 = h^2.

Therefore, h can have any value, which means there is no optimal height.

Now, let's find the radius of the cone. Since R = 2h, the radius is equal to the height.

Finally, we can find the volume of the cone using the volume formula V = (1/3) * π * r^2 * h. Plugging in the value of r = h, we get V = (1/3) * π * h^3.

So, the radius, height, and volume of the cone of greatest volume that can be made from cutting out a sector and joining the edges CA and CB are all equal to one another.