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if a rocket is launched straight up into the air with an initial velocity of 112 feet per second, it's height after t seconds is given by the formula h = 112t - 16t, where x represents the height of the rocket in feet:

A. When will the rocket reach it's maximum height

B. What is the maximum height?

(Please explain how to do the problem but if you can't that's ok. I can work with a link that will show me how to do it. Thank you for answering.)

NOT AM ACTUAL ANSWER. THIS IS BY THE SAME PERSON. IMPORTANT SIDE NOTE: the -16t is squared.

your equation is not correct, should be

h = 112t - 16t^2

This is a parabola opening downwards
You have to find the vertex, and A and B can be answered at that point
hint: the t of the vertex is -b/(2a)
plug that back into the equation to get h, the maximum

let me know what you get.

When the rocket will reach max height:
1/14 seconds

Maximum height: 7.918... Feet

BY SAME PERSON WHO ASKED QUESTION

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