posted by Jay
if a rocket is launched straight up into the air with an initial velocity of 112 feet per second, it's height after t seconds is given by the formula h = 112t - 16t, where x represents the height of the rocket in feet:
A. When will the rocket reach it's maximum height
B. What is the maximum height?
(Please explain how to do the problem but if you can't that's ok. I can work with a link that will show me how to do it. Thank you for answering.)
NOT AM ACTUAL ANSWER. THIS IS BY THE SAME PERSON. IMPORTANT SIDE NOTE: the -16t is squared.
your equation is not correct, should be
h = 112t - 16t^2
This is a parabola opening downwards
You have to find the vertex, and A and B can be answered at that point
hint: the t of the vertex is -b/(2a)
plug that back into the equation to get h, the maximum
let me know what you get.
When the rocket will reach max height:
Maximum height: 7.918... Feet
BY SAME PERSON WHO ASKED QUESTION