What is the volume occupied by 20.9g of argon gas at a pressure of 1.09atm and a temperature of 411K ?
well,
PV = nRT
plug in your numbers and solve for P.
Keep in mind: n=moles, so divide your grams by molar mass to get moles. Then, as said above, plug everything in. V=nRT/P
To calculate the volume occupied by a gas, we can use the ideal gas law equation which is:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = moles of gas
R = gas constant (0.0821 L*atm/(mol*K))
T = temperature (in Kelvin)
First, we need to convert the given values to the appropriate units:
Pressure: 1.09 atm
Temperature: 411 K
Next, we need to calculate the number of moles of argon gas. The moles (n) can be calculated using the formula:
n = mass / molar mass
The molar mass of argon (Ar) is approximately 39.948 g/mol.
Substituting the given mass (20.9 g) into the formula:
n = 20.9 g / 39.948 g/mol
Now, we have all the necessary values to calculate the volume (V). Rearranging the ideal gas law equation to solve for volume, we get:
V = (nRT) / P
Substituting the values, we can solve for the volume:
V = (n * R * T) / P
V = ((20.9 g / 39.948 g/mol) * 0.0821 L*atm/(mol*K) * 411 K) / 1.09 atm
Simplifying the expression, we can calculate the volume of argon gas.